The power supply for a pulsed nitrogen laser has a 0.076 µF capacitor with a maximum voltage rating of 30 kV.
(a) Estimate how much energy could be stored in this capacitor.
37 J
(b) If 15% of this stored electrical energy is converted to light energy in a pulse that is 8.0 microseconds long, what is the power of the laser pulse?
(No Response) W
HELp me please with the correct answer
ITS NOT 37 joules sorry, I am trying to find the joules(part a, then part b
(a) E = ½CV²
E = ½ * (0.076 * 10^-6) * (30000²)
E = 34.2 Joules
(b) 15% * 34.2 = 5.13J
P = E / t
P = 5.13 / (8 * 10^-6)
P = 641,250 Watts
hope this helps ^_^
Watts are joules/second, so take 0.15 x 37 to get 15% of the power, then divide by 8 x 10-6 seconds (8 microseconds) to get the answer.
5.85/0.000008 would be the answer in watts.
References :
(a) E = ½CV²
E = ½ * (0.076 * 10^-6) * (30000²)
E = 34.2 Joules
(b) 15% * 34.2 = 5.13J
P = E / t
P = 5.13 / (8 * 10^-6)
P = 641,250 Watts
hope this helps ^_^
References :