The power supply for a pulsed nitrogen laser has a 0.076 µF capacitor with a maximum voltage rating of 30 kV.
(a) Estimate how much energy could be stored in this capacitor.
37 J
(b) If 15% of this stored electrical energy is converted to light energy in a pulse that is 8.0 microseconds long, what is the power of the laser pulse?
(No Response) W

HELp me please with the correct answer
ITS NOT 37 joules sorry, I am trying to find the joules(part a, then part b

(a) E = ½CV²
E = ½ * (0.076 * 10^-6) * (30000²)
E = 34.2 Joules

(b) 15% * 34.2 = 5.13J
P = E / t
P = 5.13 / (8 * 10^-6)
P = 641,250 Watts

hope this helps ^_^

2 Responses

1. arsenalamie Says:
   February 27th, 2010 at 11:40 pm

   Watts are joules/second, so take 0.15 x 37 to get 15% of the power, then divide by 8 x 10-6 seconds (8 microseconds) to get the answer.

   5.85/0.000008 would be the answer in watts.
   References :

2. **PiNoY YFC** Says:
   February 28th, 2010 at 12:11 am

   (a) E = ½CV²
   E = ½ * (0.076 * 10^-6) * (30000²)
   E = 34.2 Joules

   (b) 15% * 34.2 = 5.13J
   P = E / t
   P = 5.13 / (8 * 10^-6)
   P = 641,250 Watts

   hope this helps ^_^
   References :

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